


Correct Order: The correct stability order of the carbocations is:
(CH3)3C+ > (CH3)2CH+ > CH3–CH2+ > CH3+.
Thus, the correct order of stability for the given carbocations is:
(CH3)3C+ > (CH3)2CH+ > CH3–CH2+ > CH3+.
The stability of carbocations is influenced by several factors, primarily the degree of substitution and the availability of hyper-conjugative hydrogens.
Stability Factors: Tertiary carbocations (three alkyl groups attached) are more stable than secondary (two alkyl groups), which in turn are more stable than primary (one alkyl group) and methyl (no alkyl groups). The order of stability due to hyperconjugation and inductive effects is:
Tertiary > Secondary > Primary > Methyl.
The stability of carbocations is a crucial concept in organic chemistry as it determines the ease of various reaction mechanisms such as SN1 reactions. Carbocations are positively charged species that contain a carbon atom with only six electrons in its outer shell, making it electron-deficient.
The stability of carbocations is influenced by several factors:
Considering these principles, the general order of stability for carbocations is as follows:
From the above discussion, the correct stability order of the given carbocations in the options is: \((\text{CH}_3)_3\text{C}^+ > (\text{CH}_3)_2\text{CH}^+ > \text{CH}_3\text{CH}_2^+ > \text{CH}_3^+\), which matches the correct answer image provided as Option 3.
In conclusion, the stability order of carbocations is primarily determined by hyperconjugation, inductive effects, and resonance, as seen in the above analysis.
Given below are the four isomeric compounds \(P, Q, R, S\): 
\(P\): Aromatic compound containing an \(-\mathrm{OH}\) group
\(Q\): Aromatic compound containing an \(-\mathrm{CHO}\) group (aldehyde)
\(R\): Aromatic compound containing a ketone group
\(S\): Aromatic compound containing a ketone group Identify the correct statements from below:
[A.] \(Q, R\) and \(S\) will give precipitate with \(2,4\)-DNP.
[B.] \(P\) and \(Q\) will give positive Baeyer’s test.
[C.] \(Q\) and \(R\) will give sooty flame.
[D.] \(R\) and \(S\) will give yellow precipitate with \(I_2/\mathrm{NaOH}\).
[E.] \(Q\) alone will deposit silver with Tollens’ reagent. Choose the correct option.
Match the LIST-I with LIST-II 
Choose the correct answer from the options given below:

Match the LIST-I with LIST-II for an isothermal process of an ideal gas system. 
Choose the correct answer from the options given below:
Which one of the following graphs accurately represents the plot of partial pressure of CS₂ vs its mole fraction in a mixture of acetone and CS₂ at constant temperature?

The metal-carbon bond possesses both the σ and π character in a metal carbonyl. The synergic effect produced by the metal-ligand bond strengthens the bond between the carbonyl molecule and the metal. The types of bonding that exist in metal carbonyls are as follows:
They are found to dissociate in various solutions. The stability of a coordination compound in a solution mainly depends on the degree of association between the two species involved in the state of equilibrium. For the formation of the compound quantitatively the stability of any complex is given by the magnitude of the equilibrium constant. For instance,
A + 4B→ AB4