The sequence given is: 0, 2, 6, 12, 20, 30, 42, ?. To find the next number, we observe the pattern in differences between consecutive terms:
2−0=2,
6−2=4,
12−6=6,
20−12=8,
30−20=10,
42−30=12.
Noticing that the differences are consecutive even numbers (2, 4, 6, 8, 10, 12), the next difference should be 14 (continuing this pattern). Therefore, the next term is:
42+14=56.
Thus, the appropriate next number in the series is 56.
Let \( T_r \) be the \( r^{\text{th}} \) term of an A.P. If for some \( m \), \( T_m = \dfrac{1}{25} \), \( T_{25} = \dfrac{1}{20} \), and \( \displaystyle\sum_{r=1}^{25} T_r = 13 \), then \( 5m \displaystyle\sum_{r=m}^{2m} T_r \) is equal to:
Find the missing code:
L1#1O2~2, J2#2Q3~3, _______, F4#4U5~5, D5#5W6~6