Find out difference in oxidation state of Xe in completely Hydrolysed form of XeF4 and XeF6
Solution and Explanation
\(6XeF_4+12H_2O\rightarrow 2XeO_3+4Xe+24HF+3O_2\)
in \(XeO_3, Oxidation \;state \; of Xe=+6\)
in \(XeF_4, Oxidation\;state\;of \;Xe=+4\)
\(\text{So difference in oxidation state = 2}\)
\(\text{Hence, the correct answer is : 2}\)
Top Questions on p -Block Elements
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Concepts Used:
Oxidation and Reduction
What is Oxidation?
Oxidation is a chemical process which can be explained by following four point of views
In terms of oxygen transfer
In terms of electron transfer
In terms of hydrogen transfer
In terms of oxidation number
Oxidation in Terms of Oxygen Transfer – Oxidation is gain of oxygen.
What is Reduction?
Reduction is a chemical process which can be explained by following four point of views
In terms of oxygen transfer
In terms of electron transfer
In terms of hydrogen transfer
In terms of oxidation number
Reduction in Terms of Oxygen Transfer – Reduction is loss of oxygen.
What is Redox Reaction?
A chemical reaction which involves transfer of electrons or change in oxidation number of atoms is called redox reaction.