\(6XeF_4+12H_2O\rightarrow 2XeO_3+4Xe+24HF+3O_2\)
in \(XeO_3, Oxidation \;state \; of Xe=+6\)
in \(XeF_4, Oxidation\;state\;of \;Xe=+4\)
\(\text{So difference in oxidation state = 2}\)
\(\text{Hence, the correct answer is : 2}\)
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is:
In the given circuit the sliding contact is pulled outwards such that the electric current in the circuit changes at the rate of 8 A/s. At an instant when R is 12 Ω, the value of the current in the circuit will be A.
Oxidation is a chemical process which can be explained by following four point of views
In terms of oxygen transfer
In terms of electron transfer
In terms of hydrogen transfer
In terms of oxidation number
Oxidation in Terms of Oxygen Transfer – Oxidation is gain of oxygen.
Reduction is a chemical process which can be explained by following four point of views
In terms of oxygen transfer
In terms of electron transfer
In terms of hydrogen transfer
In terms of oxidation number
Reduction in Terms of Oxygen Transfer – Reduction is loss of oxygen.
A chemical reaction which involves transfer of electrons or change in oxidation number of atoms is called redox reaction.