Find out difference in oxidation state of Xe in completely Hydrolysed form of XeF4 and XeF6
Solution and Explanation
\(6XeF_4+12H_2O\rightarrow 2XeO_3+4Xe+24HF+3O_2\)
in \(XeO_3, Oxidation \;state \; of Xe=+6\)
in \(XeF_4, Oxidation\;state\;of \;Xe=+4\)
\(\text{So difference in oxidation state = 2}\)
\(\text{Hence, the correct answer is : 2}\)
Top Questions on p -Block Elements
- $\textbf{Choose the correct statements about the hydrides of group 15 elements.}$
A. The stability of the hydrides decreases in the order \(\text{NH}_3 > \text{PH}_3 > \text{AsH}_3 > \text{SbH}_3 > \text{BiH}_3\)
B. The reducing ability of the hydrides increases in the order \(\text{NH}_3 < \text{PH}_3 < \text{AsH}_3 < \text{SbH}_3 < \text{BiH}_3\)
C. Among the hydrides, \(\text{NH}_3\) is a strong reducing agent while \(\text{BiH}_3\) is a mild reducing agent.
D. The basicity of the hydrides increases in the order \(\text{NH}_3 < \text{PH}_3 < \text{AsH}_3 < \text{SbH}_3 < \text{BiH}_3\)
Choose the most appropriate from the option given below:- JEE Main - 2024
- Chemistry
- p -Block Elements
- $\textbf{Reduction potential of ions are given below:}$
\[ \begin{array}{ccc} \text{ClO}_4^- & \text{IO}_4^- & \text{BrO}_4^- \\ E^\circ = 1.19 \, \text{V} & E^\circ = 1.65 \, \text{V} & E^\circ = 1.74 \, \text{V} \\ \end{array} \]
The correct order of their oxidising power is:- JEE Main - 2024
- Chemistry
- p -Block Elements
- Identify the correct statements about p-block elements and their compounds.
(A) Non metals have higher electronegativity than metals.
(B) Non metals have lower ionisation enthalpy than metals.
(C) Compounds formed between highly reactive nonmetals and highly reactive metals are generally ionic.
(D) The non-metal oxides are generally basic in nature.
(E) The metal oxides are generally acidic or neutral in nature.- JEE Main - 2024
- Chemistry
- p -Block Elements
- In which of the following species, the ratio of s-electrons to p-electrons is the same?
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- Chemistry
- p -Block Elements
The number of oxygen atoms present in chemical formula of fuming sulphuric acid is _______.
- JEE Main - 2024
- Chemistry
- p -Block Elements
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Concepts Used:
Oxidation and Reduction
What is Oxidation?
Oxidation is a chemical process which can be explained by following four point of views
In terms of oxygen transfer
In terms of electron transfer
In terms of hydrogen transfer
In terms of oxidation number
Oxidation in Terms of Oxygen Transfer – Oxidation is gain of oxygen.
What is Reduction?
Reduction is a chemical process which can be explained by following four point of views
In terms of oxygen transfer
In terms of electron transfer
In terms of hydrogen transfer
In terms of oxidation number
Reduction in Terms of Oxygen Transfer – Reduction is loss of oxygen.
What is Redox Reaction?
A chemical reaction which involves transfer of electrons or change in oxidation number of atoms is called redox reaction.