Question:

Find out difference in oxidation state of Xe in completely Hydrolysed form of XeF4 and XeF6

Updated On: Feb 15, 2024
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Solution and Explanation

\(6XeF_4+12H_2O\rightarrow 2XeO_3+4Xe+24HF+3O_2\)
in \(XeO_3, Oxidation \;state \; of Xe=+6\)
in \(XeF_4, Oxidation\;state\;of \;Xe=+4\)
\(\text{So difference in oxidation state = 2}\)

\(\text{Hence, the correct answer is : 2}\)

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Concepts Used:

Oxidation and Reduction

What is Oxidation? 

Oxidation is a chemical process which can be explained by following four point of views 

In terms of oxygen transfer 

In terms of electron transfer 

In terms of hydrogen transfer 

In terms of oxidation number 

Oxidation in Terms of Oxygen Transfer – Oxidation is gain of oxygen.

What is Reduction? 

Reduction is a chemical process which can be explained by following four point of views 

In terms of oxygen transfer 

In terms of electron transfer 

In terms of hydrogen transfer 

In terms of oxidation number 

Reduction in Terms of Oxygen Transfer – Reduction is loss of oxygen.

What is Redox Reaction? 

A chemical reaction which involves transfer of electrons or change in oxidation number of atoms is called redox reaction.