Question:

Find out difference in oxidation state of Xe in completely Hydrolysed form of XeF₄ and XeF₆

Updated On: Feb 15, 2024

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Solution and Explanation

$6XeF_4+12H_2O\rightarrow 2XeO_3+4Xe+24HF+3O_2$
in $XeO_3, Oxidation \;state \; of Xe=+6$
in $XeF_4, Oxidation\;state\;of \;Xe=+4$
$\text{So difference in oxidation state = 2}$

$\text{Hence, the correct answer is : 2}$

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Concepts Used:

Oxidation and Reduction

What is Oxidation?

Oxidation is a chemical process which can be explained by following four point of views

In terms of oxygen transfer

In terms of electron transfer

In terms of hydrogen transfer

In terms of oxidation number

Oxidation in Terms of Oxygen Transfer – Oxidation is gain of oxygen.

What is Reduction?

Reduction is a chemical process which can be explained by following four point of views