Figure shows three points $A, B$ and $C$ in a region of uniform electric field $ \vec{E} $ . The line $AB$ is perpendicular and $BC$ is parallel to the field lines. Then which of the following holds good?
where $V_A, V_B$ and $V_C$ represent the electric potential at the points $A, B$ and $C$ respectively.
Key Idea : Electric lines of force flow from higher potential region to lower potential region. The electric field intensity of a point in an electric field in a given direction is equal to the negative potential gradient in that direction, i.e., $E=-\frac{d V}{d x}$ The negative sign signifies that the potential decreases in the direction of electric field, i.e., electric lines of force flow from higher potential region to lower potential region. Since, $A B$ is perpendicular to field lines, so $A$ and $B$ are at same potential. Hence, $V_{A}=V_{B}>V_{C}$
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Top Questions on electrostatic potential and capacitance
The potential of a point is defined as the work done per unit charge that results in bringing a charge from infinity to a certain point.
Some major things that we should know about electric potential:
They are denoted by V and are a scalar quantity.
It is measured in volts.
Capacitance
The ability of a capacitor of holding the energy in form of an electric charge is defined as capacitance. Similarly, we can also say that capacitance is the storing ability of capacitors, and the unit in which they are measured is “farads”.
The capacitor is in Series and in Parallel as defined below;
In Series
Both the Capacitors C1 and C2 can easily get connected in series. When the capacitors are connected in series then the total capacitance that is Ctotal is less than any one of the capacitor’s capacitance.
In Parallel
Both Capacitor C1 and C2 are connected in parallel. When the capacitors are connected parallelly then the total capacitance that is Ctotal is any one of the capacitor’s capacitance.
