Question:
Fig. Reaction Consider the above reaction. The number of π electrons present in the product ‘P’ is _____ .
Consider the above reaction. The number of π electrons present in the product ‘P’ is _____ .
Updated On: Jul 6, 2024
Hide Solution
Verified By Collegedunia
Correct Answer: 2
Solution and Explanation
The correct answer is 2
The given reaction undergoes nucleophilic substitution by SN2 mechanism at room temperature
Therefore , Number of π electrons present in P are 2
Was this answer helpful?
0
0
Top Questions on Alcohols, Phenols and Ethers
- When a tertiary alcohol ($C_4H_{10}O$) reacts with 20% $H_3PO_4$ at 358 K, it gives a compound ($C_4H_8$) as the major product. The IUPAC name of this compound is:
- KCET - 2024
- Chemistry
- Alcohols, Phenols and Ethers
- PCC is:
- KCET - 2024
- Chemistry
- Alcohols, Phenols and Ethers
- 8.8 g of monohydric alcohol reacts with ethyl magnesium iodide, releasing 2240 $cm^3$ of ethane at STP. This monohydric alcohol forms a carbonyl compound that answers Tollen’s test. The alcohol is:
- KCET - 2024
- Chemistry
- Alcohols, Phenols and Ethers
- JEE Main - 2024
- Chemistry
- Alcohols, Phenols and Ethers
- Which among the following has highest boiling point?
- JEE Main - 2024
- Chemistry
- Alcohols, Phenols and Ethers
View More Questions
Questions Asked in JEE Main exam
- A rectangular loop of length 2.5 m and width 2 m is placed at 60° to a magnetic field of 4 T. The loop is removed from the field in 10 sec. The average emf induced in the loop during this time is:
- JEE Main - 2024
- Electromagnetic induction
- Two coils have mutual inductance 0.002 H. The current changes in the first coil according to the relation \( i = i_0 \sin \omega t \), where \( i_0 = 5 \, \text{A} \) and \( \omega = 50\pi \, \text{rad/s} \). The maximum value of emf in the second coil is \( \frac{\pi}{\alpha} \). The value of \( \alpha \) is ______.
- JEE Main - 2024
- Electromagnetic induction
- The 20th term from the end of the progression \[ 20, 19, \frac{1}{4}, \frac{1}{2}, \frac{3}{4}, \ldots, -129 \frac{1}{4} \] is:
- JEE Main - 2024
- Arithmetic Progression
- We have three aqueous solutions of NaCl labelled as ‘A’, ‘B’ and ‘C’ with concentration 0.1 M, 0.01M & 0.001 M, respectively. The value of vant’ Haft factor (i) for these solutions will be in the order.
- JEE Main - 2024
- Colligative Properties
- $\Delta_{vap}H^\circ$ for water is $+40.49 \, \text{kJ mol}^{-1}$ at 1 bar and $100^\circ\text{C}$. Change in internal energy for this vaporisation under same condition is .............. kJ mol$^{-1}$. (Integer answer)
(Given R = 8.3 J K$^{-1}$ mol$^{-1}$)- JEE Main - 2024
- Enthalpy change
View More Questions
Concepts Used:
Alcohols, Phenols, and Ethers - Chemical Reactions
The reaction of alcohols:
- Reaction with Metal
- Reaction with Halides
- Reaction with HNO3
- Reaction with Carboxylic Acid (Esterification)
- Dehydration of Alcohol
- Haloform Reaction
The reaction of phenols:
- Formation of Ester
- Hydrogenation
- Oxidation of Quinones
- Electrophilic Substitution
- Halogenation
The reaction of ethers:
- Contact with Air
- Halogenation of Ether
- Electrophilic Substitution Reaction
Read More: Alcohols, Phenols, and Ethers