Question:
\(FeO^{2-}_4+\underrightarrow{2.2v}\;Fe^{3+}\underrightarrow{+0.70v}\;Fe^{2+}\underrightarrow{-0.45v}\;Fe^0\)
\(E^0_{FeO_4^{2+}}\; is \;x × 10^{-3} V\). The Value of \(x\) is __
\(FeO^{2-}_4+\underrightarrow{2.2v}\;Fe^{3+}\underrightarrow{+0.70v}\;Fe^{2+}\underrightarrow{-0.45v}\;Fe^0\)
\(E^0_{FeO_4^{2+}}\; is \;x × 10^{-3} V\). The Value of \(x\) is __
\(E^0_{FeO_4^{2+}}\; is \;x × 10^{-3} V\). The Value of \(x\) is __
Updated On: Mar 24, 2024
Hide Solution
Verified By Collegedunia
Correct Answer: 1825
Solution and Explanation
The Answer is 1825
Was this answer helpful?
0
1
Top Questions on Law Of Chemical Equilibrium And Equilibrium Constant
- For the reaction in equilibrium:
N2(g) + 3H2(g) ⇌ 2NH3(g), ΔH = -Q
Reaction is favoured in forward direction by:- NEET (UG) - 2024
- Chemistry
- Law Of Chemical Equilibrium And Equilibrium Constant
- At a given temperature and pressure, the equilibrium constant values for the equilibria are given below:
\[ 3A_2 + B_2 \rightleftharpoons 2A_3B, \, K_1 \]
\[ A_3B \rightleftharpoons \frac{3}{2}A_2 + \frac{1}{2}B_2, \, K_2 \]
The relation between \( K_1 \) and \( K_2 \) is:- NEET (UG) - 2024
- Chemistry
- Law Of Chemical Equilibrium And Equilibrium Constant
- At \(-20^\circ \text{C}\) and 1 atm pressure, a cylinder is filled with an equal number of \(H_2\), \(I_2\), and \(HI\) molecules for the reaction:
\[H_2(g) + I_2(g) \rightleftharpoons 2HI(g)\] The \(K_P\) for the process is \(x \times 10^{-1}\).
\(x = ___________)
Given: \(R = 0.082 \, \text{L atm K}^{-1} \text{mol}^{-1}\)- JEE Main - 2024
- Chemistry
- Law Of Chemical Equilibrium And Equilibrium Constant
- The equilibrium $\mathrm{Cr_2O_7^{2-}} \rightleftharpoons 2\mathrm{CrO_4^{2-}}$ is shifted to the right in:
- JEE Main - 2024
- Chemistry
- Law Of Chemical Equilibrium And Equilibrium Constant
- For the given hypothetical reactions, the equilibrium constants are as follows:
\[ X \rightleftharpoons Y; \, K_1 = 1.0 \]
\[ Y \rightleftharpoons Z; \, K_2 = 2.0 \]
\[ Z \rightleftharpoons W; \, K_3 = 4.0 \]
The equilibrium constant for the reaction
\[ X \rightleftharpoons W\]
is:- JEE Main - 2024
- Chemistry
- Law Of Chemical Equilibrium And Equilibrium Constant
View More Questions
Questions Asked in JEE Main exam
- The remainder when \(64^{{32}^{32}}\) is divided by 9 is.
- JEE Main - 2024
- Number Systems
- The square of the distance of the image of the point \( (6, 1, 5) \) in the line \[ \frac{x - 1}{3} = \frac{y}{2} = \frac{z - 2}{4}, \] from the origin is _____ .
- JEE Main - 2024
- 3D Geometry
- Number of compounds from the following which cannot undergo Friedel-Crafts reactions is :____
toluene, nitrobenzene, xylene, cumene, aniline, chlorobenzene, m-nitroaniline, m-dinitrobenzene- JEE Main - 2024
- Organic Chemistry
- Two infinite current carrying wires having current I in opposite directions are shown below.
Find the magnetic field in S.I units, at point- JEE Main - 2024
- Current electricity
- The area of the region enclosed by the parabolas \( y = x^2 - 5x \) and \( y = 7x - x^2 \) is _________.
- JEE Main - 2024
- Calculus
View More Questions