Fe3+ cation gives a Prussian blue precipitate on addition of potassium ferrocyanide solution due to the formation of:
- [Fe(H2O)6]2 [Fe(CN)6]
- Fe2[Fe(CN)6]2
- Fe3[Fe(OH)2 (CN)4]2
- Fe4[Fe(CN)6]3
The Correct Option is D
Solution and Explanation
Top Questions on coordination compounds
Given below are two statements regarding conformations of n-butane. Choose the correct option.
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- The correct statement among the following is:
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Consider a weak base \(B\) of \(pK_b = 5.699\). \(x\) mL of \(0.02\) M HCl and \(y\) mL of \(0.02\) M weak base \(B\) are mixed to make \(100\) mL of a buffer of pH \(=9\) at \(25^\circ\text{C}\). The values of \(x\) and \(y\) respectively are
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- \(20.0\,\text{dm}^3\) of an ideal gas \(X\) at \(600\) K and \(0.5\) MPa undergoes isothermal reversible expansion until the pressure of the gas becomes \(0.2\) MPa. Which of the following option is correct? (Given: \(\log 2 = 0.3010\), \(\log 5 = 0.6989\))
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- From the following : (A) $[\text{Co}(\text{NH}_3)_6]^{3+}$ : Inner orbital complex, $d^2sp^3$ hybridization (B) $[\text{MnCl}_4]^{2-}$ : Outer orbital complex, $sp^3d^2$ hybridization (C) $[\text{CoF}_6]^{3-}$ : Outer orbital complex, $d^2sp^3$ hybridization (D) $[\text{FeF}_6]^{3-}$ : Outer orbital complex, $sp^3d^2$ hybridization (E) $[\text{Ni}(\text{CN})_4]^{2-}$ : Inner orbital complex, $sp^3$ hybridization Choose the correct answer from the given options.
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Questions Asked in JEE Main exam
- In a microscope of tube length $10\,\text{cm}$ two convex lenses are arranged with focal lengths $2\,\text{cm}$ and $5\,\text{cm}$. Total magnification obtained with this system for normal adjustment is $(5)^k$. The value of $k$ is ___.
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Which one of the following graphs accurately represents the plot of partial pressure of CS₂ vs its mole fraction in a mixture of acetone and CS₂ at constant temperature?
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- Three charges $+2q$, $+3q$ and $-4q$ are situated at $(0,-3a)$, $(2a,0)$ and $(-2a,0)$ respectively in the $x$-$y$ plane. The resultant dipole moment about origin is ___.
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Let \( \alpha = \dfrac{-1 + i\sqrt{3}}{2} \) and \( \beta = \dfrac{-1 - i\sqrt{3}}{2} \), where \( i = \sqrt{-1} \). If
\[ (7 - 7\alpha + 9\beta)^{20} + (9 + 7\alpha - 7\beta)^{20} + (-7 + 9\alpha + 7\beta)^{20} + (14 + 7\alpha + 7\beta)^{20} = m^{10}, \] then the value of \( m \) is ___________.- JEE Main - 2026
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Concepts Used:
Werner’s Theory of Coordination Compounds
In 1893 Werner produced a theory to explain the structures, formation and nature of bonding in the coordination compounds. This theory is known as Werner’s theory of coordination compounds.
Postulates of Werner's Theory:
The important postulates as observed by Alfred Werner throughout his experiments are as follows:
- The complex/ coordination compounds contain a central metal atom.
- The metal atoms in a coordination compound generally show two types of valency: primary valency and secondary valency.
- The primary valencies denote the oxidation state. They are ionizable and are satisfied by the negative ions.
- Secondary valencies denote the coordination number. They are non-ionizable and are fixed for every metal atom. The secondary valency is generally satisfied by the neutral molecules or negative ions.
- The metal atoms should satisfy both primary and secondary valencies.
- The secondary valency of the atom basically shows the geometry/ polyhedra of the particular coordination compound.
Limitations of Werner’s Theory:
- Though Werner explained some properties of the coordination compound, he failed to explain the colour of the coordinate compound.
- He could not explain the magnetic and optical properties of coordination compounds.
- He could not answer the question, why does the coordination sphere have a definite geometry.