Question:

Excess of $PCl_5$ reacts with conc. $H_2SO_4$ giving

Updated On: May 30, 2022
  • chlorosulphonic acid
  • thionyl chloride
  • sulphuryl chloride
  • sulphurous acid
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The Correct Option is C

Solution and Explanation

$PC1_5$ reacts with cone $H_2SO_4$ to give sulphuryl chloride by replacing its hydroxyl groups with chlorine atoms.

$\underset{\text{sulphuric acid }}{SO _{2}( OH )_{2}}+2 PCl _{5} \longrightarrow \underset{\text{sulphuryl chloride }}{SO _{2} Cl _{2}} +2 POCl _{3}+2 HCl$
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Concepts Used:

P-Block Elements

  • P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
  • P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.

P block elements consist of: