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evaluate the integral int frac sec x sqrt log sec
Question:
Evaluate the integral
\[ \int \frac{\sec x}{\sqrt{\log(\sec x + \tan x)}}\, dx \]
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Whenever an integrand contains \( \sec x \) along with \( \sec x + \tan x \), try the substitution \( u = \log(\sec x + \tan x) \).
MHT CET - 2020
MHT CET
Updated On:
Jan 30, 2026
\( \sqrt{\log(\sec x + \tan x)} + c \)
\( \sqrt{\sec x + \tan x} + c \)
\( 2\sqrt{\sec x + \tan x} + c \)
\( 2\sqrt{\log(\sec x + \tan x)} + c \)
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The Correct Option is
D
Solution and Explanation
Step 1: Choose an appropriate substitution.
Let \[ u = \log(\sec x + \tan x) \]
Step 2: Differentiate with respect to \( x \).
\[ \frac{du}{dx} = \frac{\sec x (\tan x + \sec x)}{\sec x + \tan x} = \sec x \] \[ du = \sec x \, dx \]
Step 3: Substitute into the integral.
\[ \int \frac{\sec x}{\sqrt{\log(\sec x + \tan x)}}\, dx = \int \frac{du}{\sqrt{u}} \]
Step 4: Integrate and back-substitute.
\[ \int u^{-1/2} du = 2u^{1/2} + c \] \[ = 2\sqrt{\log(\sec x + \tan x)} + c \]
Step 5: Conclusion.
\[ \boxed{2\sqrt{\log(\sec x + \tan x)} + c} \]
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