We are tasked with evaluating the integral:
\[
I = \int_{\frac{\pi}{10}}^{\frac{2\pi}{5}} \frac{\cot^3 x}{1 + \cot^3 x} \, dx
\]
1. Step 1: Use symmetry in trigonometric integrals
We can observe that \( \cot^3 x \) has a symmetry when integrated over a certain range. The integrand \( \frac{\cot^3 x}{1 + \cot^3 x} \) is symmetric over the interval from \( \frac{\pi}{10} \) to \( \frac{2\pi}{5} \), meaning that the integral results in zero because the function is odd with respect to its midpoint.
2. Step 2: Understanding the symmetry
Since the function behaves symmetrically, the integral evaluates to zero over this symmetric interval.
Thus, the answer is:
\[
I = 0
\]