Question:

Evaluate:limx2x5+2x4+x2+3x+2x4+2x3+3x25x22

Updated On: Apr 27, 2024
  • (A) 1
  • (B) 0
  • (C) -3/5
  • (D) 5/3
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The Correct Option is C

Solution and Explanation

Explanation:
On directly putting the limits, we'll find that it is of 0/0 form. So, we shall use L -Hospital's rule toevaluate the limit.I.e.=limx25x4+8x3+2x+34x3+6x2+6x5=5(2)4+8(2)3+2(2)+34(2)3+6(2)2+6(2)5=35

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