Step 1: Note that \(\sin^7 x\) is an odd function because \(\sin x\) is odd and raising to an odd power preserves oddness:
\[
\sin^7 (-x) = -\sin^7 x
\]
Step 2: The integral of an odd function over symmetric limits \([-a, a]\) is zero:
\[
\int_{-a}^a f(x) \, dx = 0 \quad \text{if } f \text{ is odd}
\]
Step 3: Therefore,
\[
\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}} \sin^7 x \, dx = 0
\]