Question:
Electromagnetic waves are incident normally on a perfectly reflecting surface having surface area \( A \). If \( I \) is the intensity of the incident electromagnetic radiation and \( c \) is the speed of light in vacuum, the force exerted by the electromagnetic wave on the reflecting surface is
Electromagnetic waves are incident normally on a perfectly reflecting surface having surface area \( A \). If \( I \) is the intensity of the incident electromagnetic radiation and \( c \) is the speed of light in vacuum, the force exerted by the electromagnetic wave on the reflecting surface is
Updated On: Dec 26, 2024
- \( \frac{2IA}{c} \)
- \( \frac{IA}{c} \)
- \( \frac{IA}{2c} \)
- \( \frac{I}{2Ac} \)
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The Correct Option is A
Solution and Explanation
The force exerted on the reflecting surface by the incident electromagnetic wave is given by:
\( F = \frac{2IA}{c} \) where \( I \) is the intensity of the incident wave, \( A \) is the area of the reflecting surface, and \( c \) is the speed of light in vacuum.
This equation arises from the momentum transfer of the electromagnetic wave to the reflecting surface.
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