Question

Efficiency of a Carnot heat engine working between the temperatures \(27^\circ \text{C}\) and \(227^\circ \text{C}\) is –

• A. 0.1
• B. 0.6
• C. 0.2
• D. 0.4

Hint:

Always convert temperatures to Kelvin before applying the Carnot efficiency formula.

Answer 1

The Correct Option is D

Efficiency \( \eta \) of a Carnot engine is given by: \[ \eta = 1 - \frac{T_C}{T_H} \] where \( T_C \) and \( T_H \) are the temperatures of the cold and hot reservoirs in Kelvin.
\[ T_C = 27^\circ\text{C} = 300\,\text{K}, \quad T_H = 227^\circ\text{C} = 500\,\text{K} \] \[ \eta = 1 - \frac{300}{500} = 1 - 0.
6 = 0.
4 \]