Question:
\(\int\frac{e^{\frac{1}{\sqrt t}}}{t\sqrt t}dt=\)
\(\int\frac{e^{\frac{1}{\sqrt t}}}{t\sqrt t}dt=\)
Updated On: May 31, 2024
- \(\frac{1}{2}e^{\frac{1}{\sqrt t}}+C\)
- \(\frac{-1}{2}e^{\frac{1}{\sqrt t}}+C\)
- \(2e^{\frac{1}{\sqrt t}}+C\)
- \(-2e^{\frac{1}{\sqrt t}}+C\)
- \(e^{\frac{1}{\sqrt t}}+C\)
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The Correct Option is D
Solution and Explanation
The correct option is (D) : \(-2e^{\frac{1}{\sqrt t}}+C\)
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