Dissolving $120\, g$ of a compound (mol. wt $= 60$) in $1000\, g$ of water gave a solution of density $1.12\, g \, mL^{-1}$. The molarity of solution is
- 1.0 M
- 2.0 M
- 2.5 M
- 4.0 M
The Correct Option is B
Solution and Explanation
Mass of solute $(w)-120\, g$
Molar mass of solute $(M)=60$
Mass of solvent $(w)=1000\, g =1000\, mL$
$\therefore$ Total mass $=1000+120=1120\, g$
$\because d=\frac{\text { Mass }}{\text{Volume}(V)}$
$\therefore$ Total volume $(V)=\frac{1120}{1.12}=1000\, mL$
$\because$ Molarity $(c)=\frac{w}{M} \times \frac{1000}{V}$
$\because$ Molarity $(c)=\frac{w}{m} \times \frac{1000}{1000}=\frac{120}{60}=2.0\, m$
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Which of the following are ambident nucleophiles?
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Identify the anomers from the following.
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Concepts Used:
Solutions
A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.
For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.
Types of Solutions:
The solutions can be classified into three types:
- Solid Solutions - In these solutions, the solvent is in a Solid-state.
- Liquid Solutions- In these solutions, the solvent is in a Liquid state.
- Gaseous Solutions - In these solutions, the solvent is in a Gaseous state.
On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types:
- Unsaturated Solution- A solution in which more solute can be dissolved without raising the temperature of the solution is known as an unsaturated solution.
- Saturated Solution- A solution in which no solute can be dissolved after reaching a certain amount of temperature is known as an unsaturated saturated solution.
- Supersaturated Solution- A solution that contains more solute than the maximum amount at a certain temperature is known as a supersaturated solution.