The Correct Answer is : \(1:2\)
\(λ=\frac{h}{\sqrt2mE_k}\)
\(\frac{λ_α}{λ_p}=\sqrt{\frac{m_p}{m_α}}\)
\(=\sqrt{\frac{1}{4}}=\frac{1}{2}\)
If \( \lambda \) and \( K \) are de Broglie wavelength and kinetic energy, respectively, of a particle with constant mass. The correct graphical representation for the particle will be:
Consider an A.P. $a_1,a_2,\ldots,a_n$; $a_1>0$. If $a_2-a_1=-\dfrac{3}{4}$, $a_n=\dfrac{1}{4}a_1$, and \[ \sum_{i=1}^{n} a_i=\frac{525}{2}, \] then $\sum_{i=1}^{17} a_i$ is equal to

The matter is made up of very tiny particles and these particles are so small that we cannot see them with naked eyes.
The three states of matter are as follows: