Question

Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 15 m, 10 m and 7 m respectively. From each can of paint 100 m² of area is painted. How many cans of paint will she need to paint the room.

Answer 1

Given that, Length (l) = 15 m, 
breadth (b) = 10 m, 
height (h) = 7 m 
Area of the hall to be painted = Area of the wall + Area of the ceiling 
= 2h (l + b) + lb 
= [2(7) (15 + 10) + 15 ×10] m² 
= [14(25) + 150] m² 
= 500 m² 
It is given that 100 m² area can be painted from each can. 
Number of cans required to paint an area of 500 m²
\(= \frac{500}{100} = 5\)
Hence, 5 cans are required to paint the walls and the ceiling of the cuboidal hall.