Question:

Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 15 m, 10 m and 7 m respectively. From each can of paint 100 m2 of area is painted. How many cans of paint will she need to paint the room.

Updated On: Jan 19, 2024
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Solution and Explanation

Given that, Length (l) = 15 m, 
breadth (b) = 10 m, 
height (h) = 7 m 
Area of the hall to be painted = Area of the wall + Area of the ceiling 
= 2h (l + b) + lb 
= [2(7) (15 + 10) + 15 ×10] m2 
= [14(25) + 150] m2 
= 500 m
It is given that 100 m2 area can be painted from each can. 
Number of cans required to paint an area of 500 m2
\(= \frac{500}{100} = 5\)
Hence, 5 cans are required to paint the walls and the ceiling of the cuboidal hall.

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