Question:
\(\int\sin2x\ cosx\ dx=\)
\(\int\sin2x\ cosx\ dx=\)
Updated On: Jun 10, 2024
- \(\frac{-1}{3}cos^3x+C\)
- \(\frac{-2}{3}cos^3x+C\)
- \(\frac{2}{3}cos^3x+C\)
- \(\frac{1}{3}cos^3x+C\)
- \(\frac{-4}{3}cos^3x+C\)
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The Correct Option is B
Solution and Explanation
The correct option is (B): \(\frac{-2}{3}cos^3x+C\)
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