Question:
Corners are cut off from an equilateral triangle T to produce a regular hexagon H. Then, the ratio of the area of H to the area of T is
Corners are cut off from an equilateral triangle T to produce a regular hexagon H. Then, the ratio of the area of H to the area of T is
Updated On: Oct 10, 2024
- 5: 6
- 4: 5
- 3: 4
- 2: 3
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The Correct Option is D
Solution and Explanation
Looking at the figure below:
we observe that the triangle can be subdivided into 9 smaller equilateral triangles that intersect at a common point.
Additionally, the hexagon contains 6 of these smaller triangles.
Therefore, the desired ratio is \(\frac{6}{9}\), which simplifies to \(\frac{2}{3}\).
we observe that the triangle can be subdivided into 9 smaller equilateral triangles that intersect at a common point.
Additionally, the hexagon contains 6 of these smaller triangles.
Therefore, the desired ratio is \(\frac{6}{9}\), which simplifies to \(\frac{2}{3}\).
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