Given: \(\tan^{-1} x + \tan^{-1} 2x = \frac{\pi}{4}\), where \(x > 0\).
\(\implies \tan^{-1} 2x = \frac{\pi}{4} - \tan^{-1} x\)
Taking tangent on both sides:
\(\implies 2x = \frac{1 - x}{1 + x}\)
\(\implies 2x(1 + x) = 1 - x\)
\(\implies 2x^2 + 3x - 1 = 0\)
Solving the quadratic equation:
\(x = \frac{-3 \pm \sqrt{9 + 8}}{4}\)
\(x = \frac{-3 \pm \sqrt{17}}{4}\)
Since \(x > 0\), the only possible solution is:
\(x = \frac{-3 + \sqrt{17}}{4}\)
Thus, the number of positive real values of \(x\) is \(1\).
The Correct answer is: 1