Consider the system of linear equations:
\[
x + 2y + z = -3,
\]
\[
3x + 3y - 2z = -1,
\]
\[
2x + 7y + 7z = -4.
\]
Determine the nature of its solutions.
Show Hint
To determine whether a system has a solution, convert it to row echelon form. If a row of the form \( 0 = c \) (where \( c \neq 0 \)) appears, the system is inconsistent and has no solution.
Step 1: Representing the system in augmented matrix form
The given system of equations can be written in matrix form as:
\[
\begin{bmatrix}
1 & 2 & 1 & | -3
3 & 3 & -2 & | -1
2 & 7 & 7 & | -4
\end{bmatrix}
\]
Step 2: Row reduction
Performing row operations to convert the augmented matrix into row echelon form:
1. Make the first pivot 1 (it is already 1 in the first row).
2. Subtract \( 3 \times \) (Row 1) from Row 2.
3. Subtract \( 2 \times \) (Row 1) from Row 3.
After performing these operations, we get:
\[
\begin{bmatrix}
1 & 2 & 1 & | -3
0 & -3 & -5 & | 8
0 & 3 & 5 & | -2
\end{bmatrix}
\]
Adding Row 2 and Row 3 to eliminate the second column entry in Row 3:
\[
\begin{bmatrix}
1 & 2 & 1 & | -3
0 & -3 & -5 & | 8
0 & 0 & 0 & | 6
\end{bmatrix}
\]
Step 3: Checking for inconsistency
The last row corresponds to the equation:
\[
0x + 0y + 0z = 6,
\]
which is a contradiction (since \( 0 \neq 6 \)). This indicates that the system has no solution.
Step 4: Conclusion
Since the system is inconsistent, it has no solution.