Question:

Consider the hyperbola $\frac{x^2}{100}-\frac{y^2}{64}=1$ with foci at $S$ and $S_1$, where $S$ lies on the positive $x$-axis Let $P$ be a point on the hyperbola, in the first quadrant Let $\angle \operatorname{SPS}_1=\alpha$, with $\alpha<\frac{\pi}{2}$ The straight line passing through the point $S$ and having the same slope as that of the tangent at $P$ to the hyperbola, intersects the straight line $S _1 P$ at $P _1$ Let $\delta$ be the distance of $P$ from the straight line $SP _1$, and $\beta= S _1 P$ Then the greatest integer less than or equal to $\frac{\beta \delta}{9} \sin \frac{\alpha}{2}$ is ______

Updated On: May 7, 2025
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Correct Answer: 7

Solution and Explanation

straight line passing through the point  S S

Given: The equation \( SP - PP = 20 \), where \( SP \) and \( PP \) are distances, and the relationship involving the variable \( \beta \), \( \delta \), and \( \alpha \).

Step 1: Equation 1

The first equation is:

\(\beta - \frac{\delta}{\sin \frac{\alpha}{2}} = 20\)

Step 2: Simplification of the equation

Next, we solve the following equation for \( \beta \) and \( \delta \):

\(\beta^2 + \delta^2 = 400 \Rightarrow 2\beta\delta \sin \frac{\alpha}{2}\)

Step 3: Relationship between \( SP \) and \( \delta \)

We are given:

\(\frac{1}{SP} = \sin \delta\)

Step 4: Calculating \( \cos \alpha \)

We now calculate \( \cos \alpha \) using the formula:

\(\cos \alpha = \frac{SP^2 + \beta^2 - 656}{2\beta \sin \frac{\alpha}{2}} \Rightarrow \cos \alpha = \frac{2\beta \sin \frac{\alpha}{2} - 256}{2\beta \sin \frac{\alpha}{2}} \Rightarrow \cos \alpha = \frac{2\beta \sin \frac{\alpha}{2} - 256}{2 \beta \sin \frac{\alpha}{2}}\)

Step 5: Applying the relation between \( \lambda \) and \( \alpha \)

Now, using the equation \( \lambda = 128 \), we get the following relationship:

\(\lambda (1 - \cos \alpha) = 128 \Rightarrow \beta \sin \frac{\alpha}{2} \cdot 2 \sin^2 \frac{\alpha}{2} = 128\)

Step 6: Solving for \( \beta \) and \( \alpha \)

We substitute the values:

\(\frac{\beta}{9} \sin \frac{\alpha}{2} \cdot 2 \sin^2 \frac{\alpha}{2} = 128 \Rightarrow \frac{\beta}{9} \sin \frac{\alpha}{2} = 64/9\)

From this, we find:

\(\left[ \frac{\beta}{9} \sin \frac{\alpha}{2} \right] = 7 \, \text{where} \, [ \cdot ] \, \text{denotes the greatest integer function.}\)

Conclusion

Therefore, the final result is \( \boxed{7} \).

Final Answer: The value of \( \left[ \frac{\beta}{9} \sin \frac{\alpha}{2} \right] \) is 7, as required by the problem.

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Concepts Used:

Conic Sections

When a plane intersects a cone in multiple sections, several types of curves are obtained. These curves can be a circle, an ellipse, a parabola, and a hyperbola. When a plane cuts the cone other than the vertex then the following situations may occur:

Let ‘β’ is the angle made by the plane with the vertical axis of the cone

  1. When β = 90°, we say the section is a circle
  2. When α < β < 90°, then the section is an ellipse
  3. When α = β; then the section is said to as a parabola
  4. When 0 ≤ β < α; then the section is said to as a hyperbola

Read More: Conic Sections