Question

Consider the following statements about manganate and permanganate ions. Identify the correct statements. A. The geometry of both manganate and permanganate ions is tetrahedral. B. The oxidation states of Mn in manganate and permanganate are +7 and +6, respectively. C. Oxidation of Mn(II) salt by peroxodisulphate gives manganate ion as the final product. D. Manganate ion is paramagnetic and permanganate ion is diamagnetic. E. Acidified permanganate ion reduces oxalate, nitrite and iodide ions.

• A. A, D and E Only
• B. A and D Only
• C. A, C and D Only
• D. A, B and E Only

Hint:

For transition metal oxoanions: - Check oxidation state of metal. - Use VSEPR for geometry. - Magnetic properties depend on d-electron count.

Answer 1

The Correct Option is D

Step 1: Geometry.
Both MnO4 2− (manganate) and MnO4 − (permanganate) have tetrahedral geometry.
So, statement A is correct.

Step 2: Oxidation states.
In MnO4 2−, manganese oxidation state is +6.
In MnO4 −, manganese oxidation state is +7.
Statement B is correct.

Step 3: Oxidation by peroxodisulphate.
Mn(II) salts oxidize to permanganate, not manganate.
So, statement C is false.

Step 4: Magnetic properties.
Manganate ion (Mn +6) has d1 electronic configuration and is paramagnetic.
Permanganate ion (Mn +7) has d0 electronic configuration and is diamagnetic.
So, statement D is correct.

Step 5: Redox properties.
Acidified permanganate ion is a strong oxidizing agent and oxidizes oxalate, nitrite, and iodide ions.
So, statement E is correct.

Correct statements:
A, B and E

Therefore, option (4) is correct.