Consider the following sequence of reactions to produce major product (A):
The molar mass of the product (A) is g mol−1. (Given molar mass in g mol−1 of C: 12,
H: 1, O: 16, Br: 80, N: 14, P: 31)
The sequence of reactions involves the following steps:
1. The first step is the bromination of nitrobenzene (CH3C6H4NO2) with Br2 and Fe, leading to the formation of bromo nitrobenzene.
2. In the second step, the nitro group (NO2) is reduced by Sn and HCl to form an amine group (NH2), resulting in the formation of aniline (CH3C6H4NH2).
3. The third step involves diazotization of aniline using NaNO2 and HCl at 273K, which forms the diazonium salt.
4. The fourth and final step is the reaction of the diazonium salt with H3PO2 and H2O, which results in the formation of 4-bromo-1-methylbenzene (C7H7Br). Now, let's calculate the molar mass of the final product (C7H7Br):
The molar mass of C7H7Br is: \[ 7 \times 12 + 7 \times 1 + 80 = 171 \, \text{g/mol} \] Thus, the molar mass of the product is 171 g/mol.
Among the following, identify the compound that is not an isomer of hexane:
Match List-I with List-II for the following reaction pattern: \[ \text{Glucose} \quad \text{Reagent} \quad \rightarrow \quad \text{Product} \quad \rightarrow \quad \text{Structural prediction} \]
Which of the following is not an aromatic compound?
Chlorobenzene reacts with bromine gas in the presence of Anhydrous AlBr_3 to yield p-Bromochlorobenzene. This reaction is classified as