Consider the following reactions: $$ \text{Cs} + O_2 (\text{excess}) \rightarrow X $$ $$ \text{Cs} + O_2 (\text{limited}) \rightarrow X $$ $$ \text{Na} + O_2 \rightarrow Y $$ Identify the correct statement about $ X $ and $ Y $.

Question

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Step 1: Understanding Alkali Metal Oxides Formation Alkali metals react with oxygen in different oxidation states, forming: - Normal oxides ($O^{2-}$): Found in small alkali metals like Li. - Peroxides ($O_2^{2-}$): Formed by Na, K. - Superoxides ($O_2^{-}$): Formed by larger alkali metals like K, Rb, and Cs. Step 2: Identifying $ X $ (Cs with O$_2$) - Cesium ($ Cs $) reacts with excess oxygen to form superoxide ($ CsO_2 $). - Superoxides contain $ O_2^- $ and are found in larger alkali metals (K, Rb, Cs). - Hence, $ X $ is a superoxide ($ CsO_2 $). Step 3: Identifying $ Y $ (Na with O$_2$) - Sodium ($ Na $) reacts with oxygen to form peroxide ($ Na_2O_2 $). - Sodium does not form superoxides under normal conditions. - Hence, $ Y $ is a peroxide ($ Na_2O_2 $). Step 4: Matching the Correct Option - $ Y $ is peroxide ($ Na_2O_2 $). - $ X $ is superoxide ($ CsO_2 $). - The correct statement is option (3): $ Y $ is peroxide and $ X $ is superoxide. \bigskip

Answer

$ Y $ is monoxide and $ X $ is superoxide

Answer

$ Y $ is peroxide and $ X $ is peroxide

Answer

$ Y $ is peroxide and $ X $ is superoxide

Answer

$ Y $ is superoxide and $ X $ is peroxide
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Consider the following reactions: \[ \text{Cs} + O_2 (\text{excess}) \rightarrow X \] \[ \text{Cs} + O_2 (\text{limited}) \rightarrow X \] \[ \text{Na} + O_2 \rightarrow Y \] Identify the correct statement about \( X \) and \( Y \).

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The Correct Option is C

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