Question:

Consider the exothermic chemical reaction O2(๐‘”)+2H2(๐‘”) โ‡Œ 2H2O(๐‘”) at equilibrium in a closed container. The correct statement(s) is/are

Updated On: Jan 11, 2025
  • At equilibrium, introduction of catalyst increases product formation
  • Equilibrium constant decreases with increase in temperature.
  • The equilibrium constant ๐พ๐‘ƒ increases with pressure.
  • Decrease in volume of reaction vessel increases product formation.
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The Correct Option is B, D

Solution and Explanation

  • (A) A catalyst only affects the rate of reaction, not the equilibrium position. Therefore, the introduction of a catalyst does not increase product formation at equilibrium.
  • (B) For an exothermic reaction, increasing the temperature shifts the equilibrium toward the reactants (Le Chatelierโ€™s Principle). Thus, the equilibrium constant decreases with an increase in temperature.
  • (C) The equilibrium constant Kp is not directly affected by pressure for reactions involving gases unless there is a change in the number of moles of gas. Since this reaction has no change in the number of moles of gas, Kp remains unaffected by pressure.
  • (D) According to Le Chatelierโ€™s Principle, reducing the volume of a reaction vessel increases the pressure and shifts the equilibrium toward the side with fewer moles of gas. In this case, the product side (2 moles of H2O) has fewer moles of gas than the reactant side (3 moles of gas), so decreasing the volume increases product formation.

Thus, the correct answers are (B) and (D)

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