A galvanometer having coil resistance 10 Ω shows a full scale deflection for a current of 3 mA. For it to measure a current of 8 A, the value of the shunt should be:
Step 1: Given Data: - Galvanometer resistance \( G = 10 \Omega \) - Full-scale deflection current \( I_g = 3 \, \text{mA} = 3 \times 10^{-3} \, \text{A} \) - Desired current to be measured \( I = 8 \, \text{A} \)
Step 2: Calculate the Shunt Resistance \( S \): - In order to convert the galvanometer into an ammeter, the shunt resistance \( S \) is given by:
\[ S = \frac{I_g \, G}{I - I_g} \]
Step 3: Substitute the Values:
\[ S = \frac{(3 \times 10^{-3}) \times 10}{8 - 0.003} \\ S = \frac{0.03}{7.997} \approx 3.75 \times 10^{-3} \, \Omega \]
So, the correct answer is : \( 3.75 \times 10^{-3} \, \Omega \)
A wire of resistance $ R $ is bent into a triangular pyramid as shown in the figure, with each segment having the same length. The resistance between points $ A $ and $ B $ is $ \frac{R}{n} $. The value of $ n $ is:
Let $ f: \mathbb{R} \to \mathbb{R} $ be a twice differentiable function such that $$ f''(x)\sin\left(\frac{x}{2}\right) + f'(2x - 2y) = (\cos x)\sin(y + 2x) + f(2x - 2y) $$ for all $ x, y \in \mathbb{R} $. If $ f(0) = 1 $, then the value of $ 24f^{(4)}\left(\frac{5\pi}{3}\right) $ is:
Resistance is the measure of opposition applied by any object to the flow of electric current. A resistor is an electronic constituent that is used in the circuit with the purpose of offering that specific amount of resistance.
R=V/I
In this case,
v = Voltage across its ends
I = Current flowing through it
All materials resist current flow to some degree. They fall into one of two broad categories:
Resistance measurements are normally taken to indicate the condition of a component or a circuit.