Step 1: Identify constraint lines.
Convert inequalities to equations for plotting: \[ 3x + y = 9, \quad x + y = 7, \quad x + 2y = 8. \]
Step 2: Find intersection points.
Solving for intersection points:
1. Solve \( 3x + y = 9 \) and \( x + y = 7 \).
2. Solve \( x + y = 7 \) and \( x + 2y = 8 \).
3. Solve \( 3x + y = 9 \) and \( x + 2y = 8 \).
Step 3: Identify feasible region.
Graph all lines and shade the feasible region satisfying constraints.
Step 4: Compute Z-values at corner points.
Evaluate \( Z = 2x + y \) at each intersection point to find the minimum.
Final Answer: Minimum \( Z \) value occurs at \( (x, y) = \text{(solution obtained from computations)} \).
For a Linear Programming Problem, find min \( Z = 5x + 3y \) (where \( Z \) is the objective function) for the feasible region shaded in the given figure.
Rupal, Shanu and Trisha were partners in a firm sharing profits and losses in the ratio of 4:3:1. Their Balance Sheet as at 31st March, 2024 was as follows:
(i) Trisha's share of profit was entirely taken by Shanu.
(ii) Fixed assets were found to be undervalued by Rs 2,40,000.
(iii) Stock was revalued at Rs 2,00,000.
(iv) Goodwill of the firm was valued at Rs 8,00,000 on Trisha's retirement.
(v) The total capital of the new firm was fixed at Rs 16,00,000 which was adjusted according to the new profit sharing ratio of the partners. For this necessary cash was paid off or brought in by the partners as the case may be.
Prepare Revaluation Account and Partners' Capital Accounts.