Compound formed when excess \(CO_2\) is passed through lime water
- \(Ca(OH)_2\)
- \(CaCO_3\)
- \(CaO\)
- \(Ca(HCO_3)_2\)
The Correct Option is D
Solution and Explanation
To solve the problem, we need to identify the compound formed when excess \( \text{CO}_2 \) is passed through lime water.
1. Understanding the Reaction:
Lime water is a solution of calcium hydroxide \( \text{Ca(OH)}_2 \) in water. When excess carbon dioxide (\( \text{CO}_2 \)) is passed through lime water, the following reactions occur:
- First, calcium hydroxide reacts with carbon dioxide to form calcium carbonate:
- If excess \( \text{CO}_2 \) is passed, the calcium carbonate reacts further with \( \text{CO}_2 \) to form calcium bicarbonate:
2. Conclusion:
When excess \( \text{CO}_2 \) is passed through lime water, the compound formed is calcium bicarbonate \( \text{Ca(HCO}_3)_2 \).
Final Answer:
The correct answer is (D) \( \text{Ca(HCO}_3)_2 \).
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