Question:

Compound A reacts with $NH _4 Cl$ and forms a compound B.
Compound B reacts with $H _2 O$ and excess of $CO _2$ to form compound $C$ which on passing through or reaction with saturated $NaCl$ solution forms sodium hydrogen carbonate Compound $A , B$ and $C$ , are respectively.

Updated On: Oct 1, 2024

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The Correct Option is C

(A) C a (O H)_{2} + 2 N H_{4} Cl Δ (B) 2 N H_{3} + C a C l_{2} + 2 H_{2} O

(B) N H_{3} + H_{2} O + (exc) C O_{2} ⟶ (C) N H_{4} H C O_{3}

(c) N H_{4} H C O_{3} + N a Cl ⟶ N a H C O_{3} ↓ + N H_{4} Cl

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