Question:
Circle diameter = 3 cm. AB and MN are diameters, perpendicular. CG ⟂ AB, AE:EB = 1:2, DF ⟂ MN, NL:LM = 1:2. Find DH in cm.
Circle diameter = 3 cm. AB and MN are diameters, perpendicular. CG ⟂ AB, AE:EB = 1:2, DF ⟂ MN, NL:LM = 1:2. Find DH in cm.
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Assign coordinates to points, apply perpendicularity and ratios to solve distances.
Updated On: Jul 31, 2025
- $2\sqrt{2} - 1$
- $\frac{(2\sqrt{2} - 1)}{2}$
- $\frac{(3\sqrt{2} - 1)}{2}$
- $\frac{(2\sqrt{2} - 1)}{3}$
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The Correct Option is B
Solution and Explanation
Using circle symmetry and chord proportionality, coordinates yield DH length as $\frac{2\sqrt{2} - 1}{2}$.
\[
\boxed{\frac{2\sqrt{2} - 1}{2}}
\]
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