Question

Choose the correct sets with respective observations: 
(1) \( \text{CuSO}_4 \) (acidified with acetic acid) + \( K_2\text{Fe(CN)}_6 \) (neutralized with NaOH) → Blue precipitate 
(2) \( 2\text{CuSO}_4 \) + \( K_2\text{Fe(CN)}_6 \) → Blue precipitate 
(3) \( 4\text{FeCl}_3 \) + \( 3\text{K}_4\text{Fe(CN)}_6 \) → \( \frac{1}{2}K_4\text{Fe(CN)}_6 \) 
(4) \( 37\text{Cl}_2 \) + \( 2\text{KFe(CN)}_6 \) → 6KC1 
In the light of the above options, choose the correct set:

• A. \( \text{CuSO}_4 \) (acidified with acetic acid) + \( K_2\text{Fe(CN)}_6 \) (neutralized with NaOH) → Blue precipitate
• B. \( 2\text{CuSO}_4 \) + \( K_2\text{Fe(CN)}_6 \) → Blue precipitate
• C. \( 4\text{FeCl}_3 \) + \( 3\text{K}_4\text{Fe(CN)}_6 \) → \( \frac{1}{2}K_4\text{Fe(CN)}_6 \)
• D. \( 37\text{Cl}_2 \) + \( 2\text{KFe(CN)}_6 \) → 6KC1

Hint:

Calculate the empirical formula

Answer 1

The Correct Option is C

To solve the given problem, we need to analyze each chemical reaction and identify which set of reactions is correct. Here are the options:
(1) \( \text{CuSO}_4 \) (acidified with acetic acid) + \( K_2\text{Fe(CN)}_6 \) (neutralized with NaOH) \(\rightarrow\) Blue precipitate
(2) \( 2\text{CuSO}_4 \) + \( K_2\text{Fe(CN)}_6 \) \(\rightarrow\) Blue precipitate
(3) \( 4\text{FeCl}_3 \) + \( 3\text{K}_4\text{Fe(CN)}_6 \) \(\rightarrow\) \( \frac{1}{2}K_4\text{Fe(CN)}_6 \)
(4) \( 37\text{Cl}_2 \) + \( 2\text{KFe(CN)}_6 \) \(\rightarrow\) 6KC1
Consideration of known inorganic chemistry reactions indicates that (3) \( 4\text{FeCl}_3 \) + \( 3\text{K}_4\text{Fe(CN)}_6 \) \(\rightarrow\) \( \frac{1}{2}K_4\text{Fe(CN)}_6 \) is the valid reaction.