Chiral complex from the following is
For identifying chiral complexes:
• Check for the absence of planes of symmetry or center of symmetry.
• Cis configurations with bidentate ligands (like en) often result in chiral complexes.
• Trans configurations are usually symmetric and achiral.
trans – [Co(NH3)4Cl2] +
cis – [PtCl2(en)2] 2+
cis – [PtCl2(NH3)2]
trans – [PtCl2(en)2] 2+
Chirality in coordination complexes occurs when the complex lacks a plane of symmetry.
- For the given complexes:
cis–[PtCl\(_2\)(en)\(_2\)]\(^{2+}\): The cis arrangement of ethylene diamine (en) ligands around the Pt center creates a chiral structure.
trans–[PtCl\(_2\)(en)\(_2\)]\(^{2+}\): The trans arrangement is symmetric, making the complex achiral.
cis–[PtCl\(_2\)(NH\(_3\))\(_2\)]: The complex has a plane of symmetry and is not chiral.
trans–[Co(NH\(_3\))\(_4\)Cl\(_2\)]\(^+\): The trans arrangement of ligands makes the complex symmetric and achiral.
Final Answer: (1) cis–[PtCl\(_2\)(en)\(_2\)]\(^{2+}\).
Give plausible explanation for:
(a) Diazonium salts of aromatic amines are stable.
(b) Aniline does not undergo Friedel-Crafts reaction.
(c) Aniline on nitration gives substantial meta product.
Let one focus of the hyperbola $ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 $ be at $ (\sqrt{10}, 0) $, and the corresponding directrix be $ x = \frac{\sqrt{10}}{2} $. If $ e $ and $ l $ are the eccentricity and the latus rectum respectively, then $ 9(e^2 + l) $ is equal to:
The largest $ n \in \mathbb{N} $ such that $ 3^n $ divides 50! is: