Chiral complex from the following is
For identifying chiral complexes:
• Check for the absence of planes of symmetry or center of symmetry.
• Cis configurations with bidentate ligands (like en) often result in chiral complexes.
• Trans configurations are usually symmetric and achiral.
trans – [Co(NH3)4Cl2] +
cis – [PtCl2(en)2] 2+
cis – [PtCl2(NH3)2]
trans – [PtCl2(en)2] 2+
Chirality in coordination complexes occurs when the complex lacks a plane of symmetry.
- For the given complexes:
cis–[PtCl\(_2\)(en)\(_2\)]\(^{2+}\): The cis arrangement of ethylene diamine (en) ligands around the Pt center creates a chiral structure.
trans–[PtCl\(_2\)(en)\(_2\)]\(^{2+}\): The trans arrangement is symmetric, making the complex achiral.
cis–[PtCl\(_2\)(NH\(_3\))\(_2\)]: The complex has a plane of symmetry and is not chiral.
trans–[Co(NH\(_3\))\(_4\)Cl\(_2\)]\(^+\): The trans arrangement of ligands makes the complex symmetric and achiral.
Final Answer: (1) cis–[PtCl\(_2\)(en)\(_2\)]\(^{2+}\).
Identify the end product (Z) in the sequence of the following reactions:
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: