Chiral complex from the following is
For identifying chiral complexes:
• Check for the absence of planes of symmetry or center of symmetry.
• Cis configurations with bidentate ligands (like en) often result in chiral complexes.
• Trans configurations are usually symmetric and achiral.
trans – [Co(NH3)4Cl2] +
cis – [PtCl2(en)2] 2+
cis – [PtCl2(NH3)2]
trans – [PtCl2(en)2] 2+
Chirality in coordination complexes occurs when the complex lacks a plane of symmetry.
- For the given complexes:
cis–[PtCl\(_2\)(en)\(_2\)]\(^{2+}\): The cis arrangement of ethylene diamine (en) ligands around the Pt center creates a chiral structure.
trans–[PtCl\(_2\)(en)\(_2\)]\(^{2+}\): The trans arrangement is symmetric, making the complex achiral.
cis–[PtCl\(_2\)(NH\(_3\))\(_2\)]: The complex has a plane of symmetry and is not chiral.
trans–[Co(NH\(_3\))\(_4\)Cl\(_2\)]\(^+\): The trans arrangement of ligands makes the complex symmetric and achiral.
Final Answer: (1) cis–[PtCl\(_2\)(en)\(_2\)]\(^{2+}\).
Which of the following are aromatic?

Give plausible explanation for:
(a) Diazonium salts of aromatic amines are stable.
(b) Aniline does not undergo Friedel-Crafts reaction.
(c) Aniline on nitration gives substantial meta product.


For the circuit shown above, the equivalent gate is:
Let \( f : \mathbb{R} \to \mathbb{R} \) be a twice differentiable function such that \[ (\sin x \cos y)(f(2x + 2y) - f(2x - 2y)) = (\cos x \sin y)(f(2x + 2y) + f(2x - 2y)), \] for all \( x, y \in \mathbb{R}. \)
If \( f'(0) = \frac{1}{2} \), then the value of \( 24f''\left( \frac{5\pi}{3} \right) \) is: