Question

Cards numbered from $107$ to $1006$ are put in a bag. A card is drawn from it at random. Find the probability that the number on the card is not divisible both by $11$ and $37$?

• (A) $0.988$
• (B) $0.998$
• (C) $0.978$
• (D) $0.968$

Answer 1

The Correct Option is B

Explanation:
Given,Number between $107$ to $1006=900$Number of possible outcomes $=n(S)=900$Numbers from $107$ to $1006$ divisible by $11$ and $37$ both $=\{407,814\}$ $=2$Numbers on cards not divisible by both $11$ and $37n(E)=900-2$$=898$$\therefore$ Probability $=\frac{n(E)(\text{ Favourable Events })}{n(S)(\text{ Possible outcomes })}$$=\frac{898}{900}$$=0.998$Hence, the correct option is (B).