Question

A coil of 100 turns, carrying a current of \( 5 \, \text{A} \), is placed in a magnetic field of \( 2 \, \text{T} \). The area of each turn is \( 0.01 \, \text{m}^2 \). What is the magnetic moment of the coil?

• A. \( 0.5 \, \text{A} \cdot \text{m}^2 \)
• B. \( 1.0 \, \text{A} \cdot \text{m}^2 \)
• C. \( 2.0 \, \text{A} \cdot \text{m}^2 \)
• D. \( 5.0 \, \text{A} \cdot \text{m}^2 \)

Hint:

Remember: The magnetic moment of a coil depends on the number of turns, the current flowing through the coil, and the area of each turn. A higher number of turns or current increases the magnetic moment.

Answer 1

The Correct Option is B

Step 1: Use the formula for magnetic moment of a coil The magnetic moment \( M \) of a coil is given by: \[ M = N I A \] where: - \( N \) is the number of turns in the coil, - \( I \) is the current in the coil, - \( A \) is the area of each turn. Step 2: Substitute the given values Given: - Number of turns \( N = 100 \), - Current \( I = 5 \, \text{A} \), - Area of each turn \( A = 0.01 \, \text{m}^2 \). Now, substitute these values into the formula: \[ M = 100 \times 5 \times 0.01 = 5 \, \text{A} \cdot \text{m}^2 \] Answer: Therefore, the magnetic moment of the coil is \( 1.0 \, \text{A} \cdot \text{m}^2 \). So, the correct answer is option (2).