
Calculate mass of Tollen’s Reagent Required?
18.70 kg
37.40 kg
9.35 kg
55.10 kg
The correct answer is option (A) : 18.70 kg
The balanced equation is :

No. of moles of NH3 formed = \(\frac{4\times 10^3}{17}\)
\(\therefore\) No. of moles of Tollen’s Reagent consumed = \(\frac{4\times 10^3}{17}\)
So, mass of Tollen’s Reagent = \(\frac{4\times 10^3}{17}\times159\)
= 18.70 kg
A square loop of sides \( a = 1 \, {m} \) is held normally in front of a point charge \( q = 1 \, {C} \). The flux of the electric field through the shaded region is \( \frac{5}{p} \times \frac{1}{\varepsilon_0} \, {Nm}^2/{C} \), where the value of \( p \) is:
A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.
A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.