\((C_7H_5O_2)_2\stackrel{ℎv}{→} [X]→2C_6H_5+2CO_2\)
Consider the above reaction and identify the intermediate ‘X’
\((C_7H_5O_2)_2\stackrel{ℎv}{→} [X]→2C_6H_5+2CO_2\)
Consider the above reaction and identify the intermediate ‘X’
The Correct Option is A
Solution and Explanation
The correct answer is (D) : 
Top Questions on Hydrocarbons
- The alkane from below having two secondary hydrogens is:
- JEE Main - 2025
- Chemistry
- Hydrocarbons
- Consider the following statements
Statement I: Benzene undergoes electrophilic substitution with excess chlorine in the presence of anhydrous AlCl$_3$
Statement - II: Benzene also undergoes electrophilic substitution with chlorine in the presence of UV light.
The correct answer is- TS EAMCET - 2025
- Chemistry
- Hydrocarbons
- An alcohol 'X' (C$_4$H$_{10}$O) reacts with conc. HCl at room temperature and gives chloride. 'X' on dehydration followed by ozonolysis gives 'Y' and 'Z'. Find 'Y' and 'Z'.
- TS EAMCET - 2025
- Chemistry
- Hydrocarbons
- The empirical formula of the compound 'D' formed in the given reaction sequence is
C₂H₄ \(\xrightarrow{Br_2|CCl_4}\) A \(\xrightarrow{(i) alc. KOH (ii) NaNH_2}\) B \(\xrightarrow{cyclic\;polymerization}\) C \(\xrightarrow{Cl_2(excess), dry\;AlCl_3, dark, cold}\) D- TS EAMCET - 2025
- Chemistry
- Hydrocarbons
- An alkyne has the molecular formula C₆H₁₀. The number of 1-alkyne isomers (excluding stereoisomers) possible for it is
- TS EAMCET - 2025
- Chemistry
- Hydrocarbons
Questions Asked in JEE Main exam
Let one focus of the hyperbola \( H : \dfrac{x^2}{a^2} - \dfrac{y^2}{b^2} = 1 \) be at \( (\sqrt{10}, 0) \) and the corresponding directrix be \( x = \dfrac{9}{\sqrt{10}} \). If \( e \) and \( l \) respectively are the eccentricity and the length of the latus rectum of \( H \), then \( 9 \left(e^2 + l \right) \) is equal to:
- JEE Main - 2025
- Conic sections
- Let \( \alpha_1 \) and \( \beta_1 \) be the distinct roots of \( 2x^2 + (\cos\theta)x - 1 = 0, \ \theta \in (0, 2\pi) \). If \( m \) and \( M \) are the minimum and the maximum values of \( \alpha_1 + \beta_1 \), then \( 16(M + m) \) equals:
- JEE Main - 2025
- Maxima and Minima
- Let the line \( x + y = 1 \) meet the circle \( x^2 + y^2 = 4 \) at the points A and B. If the line perpendicular to AB and passing through the midpoint of the chord AB intersects the circle at C and D, then the area of the quadrilateral ABCD is equal to:
- JEE Main - 2025
- Coordinate Geometry
- The number of different 5 digit numbers greater than 50000 that can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, such that the sum of their first and last digits should not be more than 8, is:
- JEE Main - 2025
- permutations and combinations
- Two identical symmetric double convex lenses of focal length \( f \) are cut into two equal parts \( L_1, L_2 \) by the AB plane and \( L_3, L_4 \) by the XY plane as shown in the figure respectively. The ratio of focal lengths of lenses \( L_1 \) and \( L_3 \) is:
Concepts Used:
Hydrocarbons
Hydrocarbons can be described as organic compounds that consists only hydrogen and carbon atoms. These compounds are of different types and thereby have distinct natures. Hydrocarbons are colorless gases and are known for discharging faint odours. These have been categorized under four major classes named as alkynes, alkanes, alkenes, and aromatic hydrocarbons.
Types of Hydrocarbons
- Saturated hydrocarbons - Saturated hydrocarbons are those compounds where there is a single bond exists between carbon atoms and are saturated with atoms of hydrogen.
- Unsaturated hydrocarbons - Hydrocarbons comprises of at least one double or triple bond between carbon atoms are known as unsaturated hydrocarbons.
- Aliphatic hydrocarbons - The term denotes the hydrocarbons formed as an outcome of the chemical degradation of fats. Aliphatic hydrocarbons are basically chemical compounds.
- Aromatic hydrocarbons - They are distinguished because of the presence of benzene rings in them. They give away distinct types of aroma. These hydrocarbons comprises of only hydrogen and carbon atoms.