The transmission range (\( d \)) of a TV tower is given by:
\( d = \sqrt{2Rh} \)
where \( R \) is the radius of the Earth and \( h \) is the height of the tower.
If the height is increased by 21%, the new height (\( h' \)) is:
\( h' = h + 0.21h = 1.21h \)
The new transmission range (\( d' \)) is:
\( d' = \sqrt{2Rh'} = \sqrt{2R(1.21h)} = \sqrt{1.21} \sqrt{2Rh} = 1.1\sqrt{2Rh} \)
Since \( d = \sqrt{2Rh} \), the new range is:
\( d' = 1.1d \)
The percentage increase in the transmission range is:
\( \frac{d' - d}{d} \times 100 = \frac{1.1d - d}{d} \times 100 = 0.1 \times 100 = 10\% \)
The transmission range increases by 10% (Option 4).
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: