Question:

By weight, 23% NaCl and 19.5% MgCl2 are present in salt water. The degree of dissociation of both salts is 100%. Find the average boiling point of salt water (inºC). (Kb = 0.52 K kg mol–1) (Nearest integer)

Updated On: Feb 7, 2024
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Solution and Explanation

The correct answer is : 113
\(\Delta T_b=iK_bm\)
\(=(\frac{23 \times 2 \times1000}{(58.5) \times 57.5}+\frac{3\times19.5\times1000}{95\times57.5})\times 0.52\)
\(=\frac{(7.86+6.16)\times0.52}{57.5}\times100 \simeq12.66\)
\(\therefore\) Boiling point \(\simeq\) 113\(^{\circ}\)C

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Concepts Used:

Solutions

A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.

For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.

Types of Solutions:

The solutions can be classified into three types:

  • Solid Solutions - In these solutions, the solvent is in a Solid-state.
  • Liquid Solutions- In these solutions, the solvent is in a Liquid state.
  • Gaseous Solutions - In these solutions, the solvent is in a Gaseous state.

On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types:

  1. Unsaturated Solution- A solution in which more solute can be dissolved without raising the temperature of the solution is known as an unsaturated solution.
  2. Saturated Solution- A solution in which no solute can be dissolved after reaching a certain amount of temperature is known as an unsaturated saturated solution.
  3. Supersaturated Solution- A solution that contains more solute than the maximum amount at a certain temperature is known as a supersaturated solution.