By weight, 23% NaCl and 19.5% MgCl2 are present in salt water. The degree of dissociation of both salts is 100%. Find the average boiling point of salt water (inºC). (Kb = 0.52 K kg mol–1) (Nearest integer)
The correct answer is : 113
\(\Delta T_b=iK_bm\)
\(=(\frac{23 \times 2 \times1000}{(58.5) \times 57.5}+\frac{3\times19.5\times1000}{95\times57.5})\times 0.52\)
\(=\frac{(7.86+6.16)\times0.52}{57.5}\times100 \simeq12.66\)
\(\therefore\) Boiling point \(\simeq\) 113\(^{\circ}\)C
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