Plot the constraints on a graph to form the feasible region. The vertices of the feasible region are determined by solving the intersection points:
\[
2x + y = 3 \quad \text{and} \quad x + 2y = 6.
\]
Substitute the vertices into \( Z = x + 2y \):
\[
Z(0, 3) = 0 + 2(3) = 6, \quad Z(1, 2) = 1 + 2(2) = 5, \quad Z(3, 0) = 3 + 2(0) = 3.
\]
The minimum value of \( Z \) is \( 3 \).