Question:

At room temperature, copper has free electron density of $8.4 \times {10}^{28}m^{-3}$. The electron drift velocity in a copper conductor of cross-sectional area of $ {10}^{-6}m^{2}$ and carrying a current of 5.4 A, will be

Updated On: Sep 3, 2024
  • $4{ms}^{-1}$
  • $0.4{ms}^{-1}$
  • $4{cms}^{-1}$
  • $0.4{mms}^{-1}$
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The Correct Option is D

Solution and Explanation

Drift velocity in a copper conductor
$V_d=\frac {i}{neA}$= $\frac {5.4}{8.4 \times {10}^{28}\times 1.6 \times {10}^{-19}\times {10}^{-6}}$
$=0.4 \times {10}^{-3}{ms}^{-1}$
$0.4{mms}^{-1}$
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Concepts Used:

Electromagnetic Induction

Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-

  1. When we place the conductor in a changing magnetic field.
  2. When the conductor constantly moves in a stationary field.

Formula:

The electromagnetic induction is mathematically represented as:-

e=N × d∅.dt

Where

  • e = induced voltage
  • N = number of turns in the coil
  • Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
  • t = time

Applications of Electromagnetic Induction

  1. Electromagnetic induction in AC generator
  2. Electrical Transformers
  3. Magnetic Flow Meter