Question

At 298 K conductivity of 0.20 M KCl solution is 0.0248 S cm\(^{-1}\). Calculate its molar conductivity.

Hint:

Molar conductivity is calculated using \( \Lambda_m = \frac{\kappa \times 1000}{C} \), where \( \kappa \) is conductivity and \( C \) is concentration.

Answer 1

Step 1: The formula for molar conductivity (\( \Lambda_m \)) is: \[ \Lambda_m = \frac{\kappa \times 1000}{C} \] where \( \kappa = 0.0248 \) S cm\(^{-1}\) and \( C = 0.20 \) M. Step 2: Substituting values: \[ \Lambda_m = \frac{0.0248 \times 1000}{0.20} = 124 \text{ S cm}^2 \text{ mol}^{-1} \]