Question:

Assuming the atom in the ground state, the expression for the magnetic field at a point (nucleus) in hydrogen atom due to circular motion of electron is \[ \mu_0 = \text{permeability of free space},\; \epsilon_0 = \text{permittivity of free space},\; m = \text{mass of electron},\; e = \text{electronic charge},\; h = \text{Planck’s constant} \]

Show Hint

The formula for magnetic field around an electron in a hydrogen atom involves various constants and the quantum mechanical nature of the electron.
Updated On: Jan 30, 2026
  • $\frac{\mu_0 e^7 \pi m^2}{8 \epsilon_0^3 h^5}$
  • $\frac{\mu_0 \pi m^2 e^5}{8 \epsilon_0^3 h^3}$
  • $\frac{\mu_0 \pi m e^4}{8 \epsilon_0^3 h^3}$
  • $\frac{\mu_0 \pi m^3 e^4}{8 \epsilon_0^2 h^2}$
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Step 1: Expression for magnetic field.
For the magnetic field at a point in hydrogen atom due to circular motion of the electron: \[ B = \frac{\mu_0 e^7 \pi m^2}{8 \epsilon_0^3 h^5} \] This is derived from the general expression for magnetic field due to circular current in an atom.
Step 2: Conclusion.
The correct expression is option (A).
Was this answer helpful?
0
0

Top Questions on Atomic Physics

View More Questions