Question:

Energy of first line of Lyman series - A Energy of second line of Balmer series - B Energy of first line of Balmer series - C Energy of second line of Lyman series - D What will be the correct decreasing order of energies of photons?

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In atomic spectra, the energy of emitted photons increases with increasing values of \( 1/n_1^2 - 1/n_2^2 \) for transitions to lower energy levels.
Updated On: Jan 23, 2026
  • \( C>A>B>D \)
  • \( D<A>B>C \)
  • \( D>A>C>B \)
  • \( D>A>B>C \)
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The Correct Option is D

Solution and Explanation

Step 1: Understand the relationship between the energies of lines.
The energy of a photon emitted in a transition between two levels in the hydrogen atom is given by the Rydberg formula: \[ E = R_H \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right) \] where: - \( R_H \) is the Rydberg constant, - \( n_1 \) and \( n_2 \) are the principal quantum numbers of the initial and final states.
Step 2: Compare the energies for different series.
- The Lyman series involves transitions to \( n_1 = 1 \) (from higher levels), and the energy of a photon increases as the transition is made from higher levels to \( n = 1 \). - The Balmer series involves transitions to \( n_1 = 2 \) (from higher levels), so the energy of photons in the Balmer series is lower than that of the Lyman series for the same transition levels.
Step 3: Compare the lines within each series.
- In the Lyman series, the energy increases with the decreasing value of \( n_2 \). Thus, the energy of the second line of the Lyman series (D) will be greater than the first line (A). - In the Balmer series, the energy decreases with increasing values of \( n_2 \). Thus, the energy of the first line of the Balmer series (C) will be greater than the second line (B).
Step 4: Order the energies.
- \( D \) (second line of Lyman series) has the highest energy. - \( A \) (first line of Lyman series) is next in energy. - \( B \) (second line of Balmer series) comes next. - \( C \) (first line of Balmer series) has the lowest energy. Thus, the correct decreasing order of energies is \( D>A>B>C \).
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