The question involves understanding the concept of angular velocity within the context of celestial bodies—specifically, the Moon revolving around the Earth and the Earth revolving around the Sun.
Angular Velocity Explanation:
Comparison:
Since \(T_{\text{moon}} < T_{\text{earth}}\), it follows that the Moon has a greater angular velocity because:
\(\omega_{\text{moon}} = \frac{2\pi}{T_{\text{moon}}} > \frac{2\pi}{T_{\text{earth}}} = \omega_{\text{earth}}\)
Analysis of Assertion and Reason:
Thus, the correct answer is: Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).
The angular speed \( \omega \) of an object is given by:
\(\omega = \frac{2\pi}{T},\)
where \( T \) is the time period.
For the moon:
- \( T_{\text{moon}} = 27 \, \text{days} \).
For the earth:
- \( T_{\text{earth}} = 365 \, \text{days} \).
Since the moon takes less time to complete one orbit around the earth compared to the earth's revolution around the sun, \( T_{\text{moon}} < T_{\text{earth}} \). Therefore:
\(\omega_{\text{moon}} > \omega_{\text{earth}}.\)
This makes both the assertion and the reason correct, and the reason is the correct explanation of the assertion.
The correct option is (A) : Both Assertion (A) and Reason (R) are the true and Reason (R) is a correct explanation of Assertion (A).
Net gravitational force at the center of a square is found to be \( F_1 \) when four particles having masses \( M, 2M, 3M \) and \( 4M \) are placed at the four corners of the square as shown in figure, and it is \( F_2 \) when the positions of \( 3M \) and \( 4M \) are interchanged. The ratio \( \dfrac{F_1}{F_2} = \dfrac{\alpha}{\sqrt{5}} \). The value of \( \alpha \) is 

The equivalent resistance between the points \(A\) and \(B\) in the given circuit is \[ \frac{x}{5}\,\Omega. \] Find the value of \(x\). 
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 
In the following \(p\text{–}V\) diagram, the equation of state along the curved path is given by \[ (V-2)^2 = 4ap, \] where \(a\) is a constant. The total work done in the closed path is: 
The work which a body needs to do, against the force of gravity, in order to bring that body into a particular space is called Gravitational potential energy. The stored is the result of the gravitational attraction of the Earth for the object. The GPE of the massive ball of a demolition machine depends on two variables - the mass of the ball and the height to which it is raised. There is a direct relation between GPE and the mass of an object. More massive objects have greater GPE. Also, there is a direct relation between GPE and the height of an object. The higher that an object is elevated, the greater the GPE. The relationship is expressed in the following manner:
PEgrav = mass x g x height
PEgrav = m x g x h
Where,
m is the mass of the object,
h is the height of the object
g is the gravitational field strength (9.8 N/kg on Earth) - sometimes referred to as the acceleration of gravity.