- The given polynomial is \(p(x) = x^2 - 2x - 3\). To find the zeroes, we solve \(x^2 - 2x - 3 = 0\) by factoring:
\[ x^2 - 2x - 3 = (x - 3)(x + 1) = 0 \]
Thus, the zeroes of the polynomial are \(x = 3\) and \(x = -1\).
- The graph of a quadratic polynomial intersects the \(x\)-axis at its zeroes. Therefore, the points where the graph intersects the \(x\)-axis are \((-1, 0)\) and \((3, 0)\), as given in the reason.
Since both the assertion and the reason are true, and the reason explains the assertion, the correct answer is (a).