- The given polynomial is \(p(x) = x^2 - 2x - 3\). To find the zeroes, we solve \(x^2 - 2x - 3 = 0\) by factoring:
\[ x^2 - 2x - 3 = (x - 3)(x + 1) = 0 \]
Thus, the zeroes of the polynomial are \(x = 3\) and \(x = -1\).
- The graph of a quadratic polynomial intersects the \(x\)-axis at its zeroes. Therefore, the points where the graph intersects the \(x\)-axis are \((-1, 0)\) and \((3, 0)\), as given in the reason.
Since both the assertion and the reason are true, and the reason explains the assertion, the correct answer is (a).
If the sum of two roots of \( x^3 + px^2 + qx - 5 = 0 \) is equal to its third root, then \( p(q^2 - 4q) = \) ?