Step 1: Understanding the given information:
We are given the arithmetic progression (AP): $21, 18, 15, 12, \dots$.
- The first term ($a$) is 21.
- The common difference ($d$) is $18 - 21 = -3$.
We need to verify the assertion and reason provided.
Step 2: Checking the assertion (A):
We need to find the sum of the first 15 terms of the AP and check if it equals zero.
The sum of the first $n$ terms of an AP is given by the formula:
\[
S_n = \frac{n}{2} \left[ 2a + (n - 1) d \right]
\]
Substituting the values $a = 21$, $d = -3$, and $n = 15$:
\[
S_{15} = \frac{15}{2} \left[ 2(21) + (15 - 1)(-3) \right]
\]
Simplifying:
\[
S_{15} = \frac{15}{2} \left[ 42 + 14(-3) \right] = \frac{15}{2} \left[ 42 - 42 \right] = \frac{15}{2} \times 0 = 0
\]
Thus, the sum of the first 15 terms is indeed zero.
Therefore, the assertion (A) is true.
Step 3: Checking the reason (R):
The formula for the sum of the first $n$ terms of an AP with first term $a$ and common difference $d$ is correctly stated as:
\[
S_n = \frac{n}{2} \left[ 2a + (n - 1) d \right]
\]
Therefore, the reason (R) is also true.
Step 4: Conclusion:
Since both the assertion (A) and reason (R) are true, the statement is correct.