The function $\sec^{-1} x$ is defined for $|x| \geq 1$, so $\sec^{-1} \left( \frac{\sqrt{3}}{2} \right)$ is not defined, as $\frac{\sqrt{3}}{2}$ lies within the interval $(-1, 1)$, where the secant function is not defined. Hence, the set of values of $\sec^{-1} \left( \frac{\sqrt{3}}{2} \right)$ is indeed a null set. Thus, both the assertion and the reason are correct.