Given below are two statements, one is labelled as Assertion A and the other is labelled as Reason R
Assertion A: Beryllium has less negative value of reduction potential compared to the other alkaline earth metals
Reason R: Beryllium has large hydration energy due to small size of \(Be ^{2+}\) but relatively large value of atomization enthalpy
In the light of the above statements, choose the most appropriate answer from the options given below
Reduction potential is influenced by hydration energy, ion size, and atomization enthalpy. Smaller ions like \(Be^{2+}\) have higher hydration energy, stabilizing the ion in aqueous solutions.
Beryllium has a less negative reduction potential compared to other alkaline earth metals (AEM). This is because of:
• High hydration energy: Due to the small size of the Be2+ ion, the hydration energy is very large, which stabilizes the ion in aqueous solutions.
• Large atomization enthalpy: Beryllium has strong metallic bonding due to its small atomic size, which increases its atomization enthalpy. These factors reduce the tendency of beryllium to get reduced, leading to a less negative
reduction potential.
Since the reason (R) explains why beryllium has a less negative reduction potential, both A and R are correct, and R is the correct explanation of A.
Given below are two statements.
In the light of the above statements, choose the correct answer from the options given below:
Given below are two statements:
Statement I: Nitrogen forms oxides with +1 to +5 oxidation states due to the formation of $\mathrm{p} \pi-\mathrm{p} \pi$ bond with oxygen.
Statement II: Nitrogen does not form halides with +5 oxidation state due to the absence of d-orbital in it.
In the light of the above statements, choose the correct answer from the options given below:
Given below are the pairs of group 13 elements showing their relation in terms of atomic radius. $(\mathrm{B}<\mathrm{Al}),(\mathrm{Al}<\mathrm{Ga}),(\mathrm{Ga}<\mathrm{In})$ and $(\mathrm{In}<\mathrm{Tl})$ Identify the elements present in the incorrect pair and in that pair find out the element (X) that has higher ionic radius $\left(\mathrm{M}^{3+}\right)$ than the other one. The atomic number of the element (X) is
Match List-I with List-II: List-I